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Difficulty: MediumIPv4 Addressing and Subnetting

A systems engineer is provisioning a dedicated storage area network management VLAN using the IPv4 subnet block 192.168.100.128/26192.168.100.128/26. What is the broadcast IP address for this network segment?

Answer: 192.168.100.191

Answer

192.168.100.191
For the network block 192.168.100.128/26192.168.100.128/26, the subnet mask is 255.255.255.192255.255.255.192, yielding subnets spaced in increments of 64 in the fourth octet (00, 6464, 128128, 192192). The subnet starting at 192.168.100.128192.168.100.128 spans up to 192.168.100.191192.168.100.191, making 192.168.100.191192.168.100.191 the broadcast address.

Step-by-Step Solution

1
Determine the prefix length and host bits
A /26/26 prefix leaves 32−26=632 - 26 = 6 bits for host addressing.
Calculating host bits identifies the size of each subnet block.
2
Calculate the block size in the fourth octet
The block size is 26=642^6 = 64.
Each subnet in this block increments by 64 in the last octet.
3
Find the next network address and determine the broadcast address
The current network address is 192.168.100.128192.168.100.128. The next subnet starts at 128+64=192.168.100.192128 + 64 = 192.168.100.192. Subtracting 1 yields the broadcast address 192.168.100.191192.168.100.191.
The broadcast address is always the last IP address in the subnet block immediately preceding the next network boundary.

Key Concept

IPv4 Broadcast Address Calculation
Estimated Time:1m 30s
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Topics

IPv4 Addressing and Subnetting

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