Question

Difficulty: EasyIPv4 Addressing and Subnetting

A network technician is assigning static IP addresses to end-user devices within a subnet configured as 192.168.1.0/26192.168.1.0/26. Which of the following IP addresses are valid usable host addresses on this network segment? (Select TWO.)

  1. 192.168.1.15Answer
  2. 192.168.1.50Answer
  3. C
    192.168.1.0
  4. D
    192.168.1.63
  5. E
    192.168.1.64

Answer

The valid usable host IP addresses are 192.168.1.15 and 192.168.1.50.
For the CIDR prefix /26/26, the subnet mask is 255.255.255.192255.255.255.192, yielding a total block size of 6464 IP addresses (192.168.1.0192.168.1.0 to 192.168.1.63192.168.1.63). Subtracting the network address (192.168.1.0192.168.1.0) and the broadcast address (192.168.1.63192.168.1.63) leaves a usable host range of 192.168.1.1192.168.1.1 through 192.168.1.62192.168.1.62. Both 192.168.1.15 and 192.168.1.50 fall within this valid range.

Step-by-Step Solution

1
Determine the block size for the CIDR prefix /26
Block size = 2(3226)=26=642^{(32-26)} = 2^6 = 64 IP addresses
Calculating the total number of IP addresses in the subnet block.
2
Identify the network ID and broadcast address
Network ID = 192.168.1.0192.168.1.0, Broadcast address = 192.168.1.63192.168.1.63
The network address is the first IP address (192.168.1.0192.168.1.0) and the broadcast address is the last IP address (192.168.1.0+641=192.168.1.63192.168.1.0 + 64 - 1 = 192.168.1.63).
3
Define the usable host address range
Usable host range = 192.168.1.1192.168.1.1 through 192.168.1.62192.168.1.62
Usable hosts exclude the network ID and broadcast address.
4
Evaluate choices against the usable range
192.168.1.15 and 192.168.1.50 lie inside the valid range [192.168.1.1, 192.168.1.62]
192.168.1.0 is the network ID, 192.168.1.63 is the broadcast address, and 192.168.1.64 belongs to the next subnet.

Key Concept

Subnet Host Ranges and Reserved Addresses
Rate this question