Question

Difficulty: MediumFunction Definitions, Evaluation, and Custom Operators

For all real numbers aa and bb, the custom binary operation \star is defined by ab=a22b2+aba \star b = a^2 - 2b^2 + ab. The function gg is defined by g(x)=x3g(x) = x \star 3. What is the positive value of xx for which g(x)=10g(x) = 10?

  1. 4Answer
  2. B
    1
  3. C
    7
  4. D
    28\sqrt{28}
  5. E
    3

Answer

The positive value of xx for which g(x)=10g(x) = 10 is 44.
Evaluating g(x)=x3g(x) = x \star 3 gives x22(3)2+x(3)=x2+3x18x^2 - 2(3)^2 + x(3) = x^2 + 3x - 18. Setting this expression equal to 1010 produces the quadratic equation x2+3x28=0x^2 + 3x - 28 = 0. Factoring yields (x+7)(x4)=0(x + 7)(x - 4) = 0, giving solutions x=7x = -7 and x=4x = 4. Since xx must be positive, the correct value is 44.

Step-by-Step Solution

1
Apply the definition of the custom binary operator \star to find g(x)g(x).
g(x)=x3=x22(3)2+x(3)=x218+3x=x2+3x18g(x) = x \star 3 = x^2 - 2(3)^2 + x(3) = x^2 - 18 + 3x = x^2 + 3x - 18
Substitute a=xa = x and b=3b = 3 into the given formula ab=a22b2+aba \star b = a^2 - 2b^2 + ab.
2
Set the function expression equal to 1010 and rearrange into standard quadratic form.
x2+3x18=10    x2+3x28=0x^2 + 3x - 18 = 10 \implies x^2 + 3x - 28 = 0
Subtract 1010 from both sides to form a quadratic equation equal to zero.
3
Factor the quadratic equation to find the values of xx.
(x+7)(x4)=0    x=7 or x=4(x + 7)(x - 4) = 0 \implies x = -7 \text{ or } x = 4
Find two numbers that multiply to 28-28 and add to 33, which are 77 and 4-4.
4
Select the positive value of xx as specified in the stem.
x=4x = 4
The question asks specifically for the positive value of xx.

Key Concept

Evaluating non-commutative custom operators and solving polynomial equations resulting from function evaluations.
Estimated Time:2m 0s
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