Question

Difficulty: HardFunction Definitions, Evaluation, and Custom Operators

For all real numbers xx except 00 and 11, the function f(x)f(x) satisfies the relation f(x)+2f(11x)=9xf(x) + 2f\left(\frac{1}{1-x}\right) = 9x. What is the value of f(2)f(2)?

Answer: 6

Answer

The value of f(2)f(2) is 66.
Evaluating the functional equation f(x)+2f(11x)=9xf(x) + 2f\left(\frac{1}{1-x}\right) = 9x at the values x=2x = 2, x=1x = -1, and x=12x = \frac{1}{2} creates a system of three linear equations in terms of f(2)f(2), f(1)f(-1), and f(12)f\left(\frac{1}{2}\right). Solving this system yields 9f(2)=549f(2) = 54, which simplifies directly to f(2)=6f(2) = 6.

Step-by-Step Solution

1
Evaluate the functional equation at x=2x = 2
f(2)+2f(112)=9(2)    f(2)+2f(1)=18f(2) + 2f\left(\frac{1}{1-2}\right) = 9(2) \implies f(2) + 2f(-1) = 18
Applying the input x=2x = 2 creates an equation connecting f(2)f(2) and f(1)f(-1).
2
Evaluate the functional equation at x=1x = -1
f(1)+2f(11(1))=9(1)    f(1)+2f(12)=9f(-1) + 2f\left(\frac{1}{1-(-1)}\right) = 9(-1) \implies f(-1) + 2f\left(\frac{1}{2}\right) = -9
Evaluating at the new input x=1x = -1 generates a second equation connecting f(1)f(-1) and f(12)f\left(\frac{1}{2}\right).
3
Evaluate the functional equation at x=12x = \frac{1}{2}
f(12)+2f(111/2)=9(12)    f(12)+2f(2)=4.5f\left(\frac{1}{2}\right) + 2f\left(\frac{1}{1-1/2}\right) = 9\left(\frac{1}{2}\right) \implies f\left(\frac{1}{2}\right) + 2f(2) = 4.5
Evaluating at x=12x = \frac{1}{2} completes the cyclic chain by linking back to f(2)f(2).
4
Solve the system of three linear equations for f(2)f(2)
From equation 3, f(12)=4.52f(2)f\left(\frac{1}{2}\right) = 4.5 - 2f(2). Substituting into equation 2 yields f(1)=4f(2)18f(-1) = 4f(2) - 18. Substituting into equation 1 gives f(2)+2(4f(2)18)=18    9f(2)=54    f(2)=6f(2) + 2(4f(2) - 18) = 18 \implies 9f(2) = 54 \implies f(2) = 6.
Eliminating f(12)f\left(\frac{1}{2}\right) and f(1)f(-1) isolated f(2)f(2) to find its exact numerical value.

Key Concept

Cyclic Functional Equations and Substitution Systems
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