Question

Difficulty: MediumRate, Time, and Distance Problems

A service technician travels by boat from Pier 1 to an offshore platform at a constant speed of 3030 miles per hour. Immediately upon arrival, the technician returns along the exact same route to Pier 1 at a constant speed of 6060 miles per hour. If the entire round-trip journey takes 33 hours, what is the total distance, in miles, traveled by the technician?

  1. A
    6060
  2. B
    9090
  3. 120120Answer
  4. D
    135135
  5. E
    180180

Answer

120 miles
To find the total distance, we must account for the time spent on each leg. Letting dd be the one-way distance, the outbound time is d30\frac{d}{30} and the return time is d60\frac{d}{60}. Summing these gives d30+d60=3\frac{d}{30} + \frac{d}{60} = 3 hours, which simplifies to 3d60=3\frac{3d}{60} = 3, leading to d=60d = 60 miles. Since the technician completes a round trip, the total distance traveled is 2×60=1202 \times 60 = 120 miles.

Step-by-Step Solution

1
Define variables for distance and express travel times for each leg of the trip.
Let dd be the one-way distance between Pier 1 and the offshore platform. Time to reach platform: t1=d30t_1 = \frac{d}{30} hours. Time to return: t2=d60t_2 = \frac{d}{60} hours.
Time equals distance divided by speed (t=dvt = \frac{d}{v}).
2
Set up an equation using total time.
t1+t2=d30+d60=3t_1 + t_2 = \frac{d}{30} + \frac{d}{60} = 3
The total duration for both legs combined is given as 33 hours.
3
Solve for the one-way distance dd.
Find a common denominator: 2d60+d60=3d60=d20=3    d=60\frac{2d}{60} + \frac{d}{60} = \frac{3d}{60} = \frac{d}{20} = 3 \implies d = 60 miles.
Combining fractional terms allows isolated calculation of the one-way distance.
4
Calculate the total round-trip distance.
Total distance =2d=2×60=120= 2d = 2 \times 60 = 120 miles.
The question specifically asks for the total distance traveled during the entire round trip.

Key Concept

Average Speed and Total Distance in Round-Trip Scenarios
Estimated Time:2m 0s
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