Question

Difficulty: MediumExponents, Roots, and Powers of Integers

If xx and yy are positive integers such that 3x5y=6753^x \cdot 5^y = 675, what is the value of 2x+y3xy2^{x+y} \cdot 3^{x-y}?

  1. A
    32
  2. B
    36
  3. 96Answer
  4. D
    192
  5. E
    288

Answer

96
Prime factorizing 675675 gives 33523^3 \cdot 5^2. Equating the exponents yields x=3x = 3 and y=2y = 2. Substituting these into 2x+y3xy2^{x+y} \cdot 3^{x-y} yields 2531=323=962^5 \cdot 3^1 = 32 \cdot 3 = 96.

Step-by-Step Solution

1
Find the prime factorization of 675.
675=27×25=3352675 = 27 \times 25 = 3^3 \cdot 5^2
Decomposing 675 into prime factors allows matching the exponents of prime bases 3 and 5.
2
Equate exponents of matching prime bases to determine xx and yy.
x=3x = 3 and y=2y = 2
Since 3 and 5 are prime numbers, the prime factorization of 675 is unique.
3
Evaluate the target expression 2x+y3xy2^{x+y} \cdot 3^{x-y}.
23+2332=2531=323=962^{3+2} \cdot 3^{3-2} = 2^5 \cdot 3^1 = 32 \cdot 3 = 96
Substitute the determined values of xx and yy into the target power expression.

Key Concept

Prime Factorization and Exponent Properties
Estimated Time:1m 30s
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