Question

Difficulty: HardGreatest Common Divisor (GCD) and Least Common Multiple (LCM)

Two positive integers mm and nn satisfy m<nm < n. Their greatest common divisor is 1818 and their least common multiple is 1,0801,080. If mm is not divisible by 2727 and nn is not divisible by 55, what is the value of nmn - m?

Answer: 126

Answer

The value of nmn - m is 126126.
By writing m=18am = 18a and n=18bn = 18b with GCD(a,b)=1\text{GCD}(a,b) = 1, we find ab=60a \cdot b = 60. Evaluating all coprime factor pairs (a,b)(a, b) shows that only (5,12)(5, 12) satisfies all constraints (m=90m = 90 is not a multiple of 2727, and n=216n = 216 is not a multiple of 55). The difference is 21690=126216 - 90 = 126.

Step-by-Step Solution

1
Relate GCD, LCM, and coprime factors.
Let m=18am = 18a and n=18bn = 18b, where GCD(a,b)=1\text{GCD}(a, b) = 1 and a<ba < b. Then ab=108018=60a \cdot b = \frac{1080}{18} = 60.
The product of two positive integers equals the product of their GCD and LCM.
2
Determine all coprime factor pairs of 6060.
The coprime pairs (a,b)(a, b) with a<ba < b such that ab=60a \cdot b = 60 are (1,60)(1, 60), (3,20)(3, 20), (4,15)(4, 15), and (5,12)(5, 12).
Since GCD(a,b)=1\text{GCD}(a, b) = 1, prime factors of 60=223560 = 2^2 \cdot 3 \cdot 5 cannot be shared between aa and bb.
3
Apply the given constraints to eliminate invalid pairs.
The pair (5,12)(5, 12) is the only pair satisfying both conditions: m=90m = 90 is not divisible by 2727, and n=216n = 216 is not divisible by 55.
Pairs (1,60)(1,60) and (4,15)(4,15) yield nn divisible by 55; pair (3,20)(3,20) yields m=54m=54 which is divisible by 2727.
4
Compute the final difference nmn - m.
nm=21690=126n - m = 216 - 90 = 126.
Subtract mm from nn using the valid values found.

Key Concept

Properties of GCD and LCM, prime factorization, and coprime factor pairs
Estimated Time:2m 0s
Rate this question