Question

Difficulty: MediumProbability of Independent and Dependent Events

A committee of 1010 members consists of 55 senior directors and 55 junior associates. If 33 committee members are selected at random one after another without replacement, what is the probability that exactly 22 of the selected members are senior directors?

  1. A
    536\frac{5}{36}
  2. B
    38\frac{3}{8}
  3. 512\frac{5}{12}Answer
  4. D
    25144\frac{25}{144}
  5. E
    12\frac{1}{2}

Answer

The probability that exactly 22 of the selected members are senior directors is 512\frac{5}{12}.
The correct answer is found by taking into account that the selections are dependent events without replacement. The probability of selecting senior directors on the first two draws and a junior associate on the third is 510×49×58=536\frac{5}{10} \times \frac{4}{9} \times \frac{5}{8} = \frac{5}{36}. Because there are 33 possible mutually exclusive orders to select 22 senior directors and 11 junior associate, multiplying 536\frac{5}{36} by 33 gives the final probability of 512\frac{5}{12}.

Step-by-Step Solution

1
Calculate the probability of drawing Senior, Senior, Junior in that specific order without replacement.
P(Senior1)×P(Senior2Senior1)×P(Junior3Senior1Senior2)=510×49×58=100720=536P(\text{Senior}_1) \times P(\text{Senior}_2 \mid \text{Senior}_1) \times P(\text{Junior}_3 \mid \text{Senior}_1 \cap \text{Senior}_2) = \frac{5}{10} \times \frac{4}{9} \times \frac{5}{8} = \frac{100}{720} = \frac{5}{36}
Because draws are made without replacement, the sample space and favorable outcomes decrease with each draw.
2
Determine the number of distinct orderings of 22 Senior directors and 11 Junior associate.
(32)=3\binom{3}{2} = 3 orderings: (Senior, Senior, Junior), (Senior, Junior, Senior), and (Junior, Senior, Senior).
The question asks for exactly 22 senior directors regardless of the order in which they are selected.
3
Multiply the single-sequence probability by the total number of valid orderings.
3×536=1536=5123 \times \frac{5}{36} = \frac{15}{36} = \frac{5}{12}
Since each distinct ordering is mutually exclusive and has the same probability, the total probability is the sum across all 33 orderings.

Key Concept

Probability of Dependent Events (Sampling Without Replacement)
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