Question

Difficulty: EasyExponents, Roots, and Powers of Integers

If 3x92=3103^x \cdot 9^2 = 3^{10}, what is the value of xx?

Answer: 6

Answer

The value of xx is 6.
Rewriting 929^2 as (32)2=34(3^2)^2 = 3^4 converts the expression to a common base of 33. Applying the product rule gives 3x34=3x+43^x \cdot 3^4 = 3^{x+4}. Setting the exponent x+4x+4 equal to 1010 yields x=6x = 6.

Step-by-Step Solution

1
Express all powers using the common base 3
92=(32)2=349^2 = (3^2)^2 = 3^4
Converting terms to a common base allows application of exponent rules.
2
Apply the product rule for exponents
3x34=3x+43^x \cdot 3^4 = 3^{x+4}
When multiplying terms with identical bases, add the exponents.
3
Equate the exponents and solve for x
x+4=10    x=6x + 4 = 10 \implies x = 6
If bm=bnb^m = b^n for b>0b > 0 and b1b \neq 1, then m=nm = n.

Key Concept

Exponent rules with base conversion and product of powers
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