Question

Difficulty: MediumFunction Definitions, Evaluation, and Custom Operators

For all real numbers xx and yy, the custom binary operator \odot is defined by xy=x2yxy2x \odot y = x^2 y - x y^2. The function ff is defined by f(x)=x3f(x) = x \odot 3. What is the value of f(f(2))f(f(2))?

Answer: 162

Answer

The value of f(f(2))f(f(2)) is 162.
To evaluate the nested function f(f(2))f(f(2)), first determine f(2)f(2) using the definition f(x)=x3f(x) = x \odot 3. Applying the definition of the custom operator xy=x2yxy2x \odot y = x^2 y - x y^2 with x=2x = 2 and y=3y = 3 yields 23=(2)2(3)(2)(3)2=1218=62 \odot 3 = (2)^2(3) - (2)(3)^2 = 12 - 18 = -6. Then, evaluate f(6)=63=(6)2(3)(6)(3)2=108(54)=162f(-6) = -6 \odot 3 = (-6)^2(3) - (-6)(3)^2 = 108 - (-54) = 162.

Step-by-Step Solution

1
Evaluate the inner function expression f(2)
f(2) = 2 \odot 3 = (2)^2(3) - (2)(3)^2 = 12 - 18 = -6
By definition, f(x) = x \odot 3. Substituting x = 2 gives 2 \odot 3, which applies the custom operator definition x^2 y - x y^2.
2
Evaluate the outer function expression f(f(2)) = f(-6)
f(-6) = -6 \odot 3 = (-6)^2(3) - (-6)(3)^2 = 36(3) - (-54) = 108 + 54 = 162
Substitute the inner result -6 into the function f(x).

Key Concept

Custom Binary Operators and Nested Function Evaluation
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