Question

Difficulty: HardWork Rate and Combined Work

A municipal water treatment facility utilizes three primary purification units—Unit P, Unit Q, and Unit R—to process large water batches. Operating alone at its constant rate, Unit P can process a full batch in 1212 hours, Unit Q can process a full batch in 1818 hours, and Unit R can process a full batch in 3636 hours. All three units begin processing a batch together. After 33 hours, Unit P stops operating due to scheduled maintenance. Unit Q and Unit R continue operating together for an additional 22 hours, after which Unit Q is shut down. Unit R then completes the remainder of the batch working alone. How many total hours does it take from start to finish to process the complete batch?

Answer: 17 hours

Answer

The total time required to process the complete batch from start to finish is 17 hours.
To find the total time from start to finish, analyze the work completed in each of the three stages:

1. In Stage 1 (3 hours), all three units operate together. Their combined rate is 112+118+136=3+2+136=636=16\frac{1}{12} + \frac{1}{18} + \frac{1}{36} = \frac{3 + 2 + 1}{36} = \frac{6}{36} = \frac{1}{6} batch per hour. In 33 hours, they complete 3×16=123 \times \frac{1}{6} = \frac{1}{2} of the total batch.

2. In Stage 2 (2 hours), Unit P stops and Units Q and R continue together. Their combined rate is 118+136=2+136=336=112\frac{1}{18} + \frac{1}{36} = \frac{2 + 1}{36} = \frac{3}{36} = \frac{1}{12} batch per hour. In 22 hours, they complete 2×112=162 \times \frac{1}{12} = \frac{1}{6} of the total batch.

3. After Stage 2, the total fraction of work completed is 12+16=46=23\frac{1}{2} + \frac{1}{6} = \frac{4}{6} = \frac{2}{3} of the batch. The remaining fraction of work is 123=131 - \frac{2}{3} = \frac{1}{3} of the batch.

4. In Stage 3, Unit R completes the remaining 13\frac{1}{3} batch alone at its rate of 136\frac{1}{36} batch per hour. The time taken by Unit R is 1/31/36=12\frac{1/3}{1/36} = 12 hours.

Adding the durations of all three stages gives 3+2+12=173 + 2 + 12 = 17 total hours.

Step-by-Step Solution

1
Calculate individual work rates
Rate of P = 112\frac{1}{12} batch/hr, Rate of Q = 118\frac{1}{18} batch/hr, Rate of R = 136\frac{1}{36} batch/hr
Work rate is the reciprocal of the total time required to complete one entire job.
2
Calculate work done during Stage 1 (first 3 hours)
Combined rate of P, Q, R = 112+118+136=636=16\frac{1}{12} + \frac{1}{18} + \frac{1}{36} = \frac{6}{36} = \frac{1}{6} batch/hr. Work done = 3×16=123 \times \frac{1}{6} = \frac{1}{2} batch
All three units operate simultaneously for 3 hours.
3
Calculate work done during Stage 2 (next 2 hours)
Combined rate of Q and R = 118+136=336=112\frac{1}{18} + \frac{1}{36} = \frac{3}{36} = \frac{1}{12} batch/hr. Work done = 2×112=162 \times \frac{1}{12} = \frac{1}{6} batch
Unit P stops working, leaving Q and R to operate together for 2 hours.
4
Determine remaining work and time required for Stage 3
Remaining work = 1(12+16)=131 - \left(\frac{1}{2} + \frac{1}{6}\right) = \frac{1}{3} batch. Time for R alone = 1/31/36=12\frac{1/3}{1/36} = 12 hours
Unit R must complete the remaining fraction of the batch operating alone at its constant rate.
5
Calculate total elapsed time
3 hours+2 hours+12 hours=17 hours3\text{ hours} + 2\text{ hours} + 12\text{ hours} = 17\text{ hours}
Sum the durations of all three distinct operational stages.

Key Concept

Combined Work Rate in Multi-Stage Work Scenarios
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