Question

Difficulty: MediumEven-Odd Properties and Sign Rules

Let aa, bb, and cc be non-zero integers such that ab<0\frac{a}{b} < 0, a3bc>0a^3 b c > 0, and a+ba + b is an odd integer. Which of the following statements must be true? Select all such statements.

  1. c<0c < 0Answer
  2. aba b is an even integerAnswer
  3. C
    ac>0a c > 0
  4. D
    a2+ca^2 + c is an even integer
  5. E
    b+c<0b + c < 0

Answer

The statements 'c<0c < 0' and 'aba b is an even integer' must be true.
The statement 'c<0c < 0' must be true because ab<0\frac{a}{b} < 0 forces ab<0a b < 0, and since a3bc=a2(ab)ca^3 b c = a^2 (a b) c with a2>0a^2 > 0, cc must be negative to yield a positive product. The statement 'aba b is an even integer' must be true because an odd sum a+ba + b requires one variable to be even and the other to be odd, making their product even.

Step-by-Step Solution

1
Determine the sign relationship between aa and bb.
aa and bb have opposite signs, so ab<0a b < 0.
The quotient ab<0\frac{a}{b} < 0 implies the numerator and denominator have different signs.
2
Determine the sign of cc using a3bc>0a^3 b c > 0.
c<0c < 0.
Rewrite a3bca^3 b c as a2(ab)ca^2 \cdot (a b) \cdot c. Since a0a \neq 0, a2>0a^2 > 0. Since ab<0a b < 0, the product a2(ab)<0a^2 (a b) < 0. For the entire product a2(ab)ca^2 (a b) c to be positive, cc must be negative.
3
Analyze the parity of aa and bb from a+ba + b being odd.
One of aa or bb is even and the other is odd, so aba b must be even.
An odd sum of two integers requires one even and one odd addend. The product of an even integer and any integer is always even.
4
Test the remaining options for counterexamples.
The statements 'ac>0a c > 0', 'a2+ca^2 + c is an even integer', and 'b+c<0b + c < 0' can be false under valid assignments.
For example, if a=2a = 2, b=1b = -1, and c=3c = -3, then ab=2<0\frac{a}{b} = -2 < 0, a3bc=8(1)(3)=24>0a^3 b c = 8(-1)(-3) = 24 > 0, and a+b=1a + b = 1 (odd). Here, ac=6<0a c = -6 < 0, a2+c=43=1a^2 + c = 4 - 3 = 1 (odd), and b+c=4<0b + c = -4 < 0, but setting b=5,a=2,c=1b = 5, a = -2, c = -1 gives b+c=4>0b + c = 4 > 0.

Key Concept

Deducing sign and parity properties of integers
Estimated Time:1m 30s
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