Question

Difficulty: MediumSystems of Linear Equations

If the pair (x,y)(x, y) satisfies the system of linear equations below, what is the value of xyx - y?

3x5y=142x+7y=1\begin{aligned} 3x - 5y &= 14 \\ 2x + 7y &= -1 \end{aligned}
  1. A
    -1
  2. B
    2
  3. C
    3
  4. 4Answer
  5. E
    5

Answer

The value of xyx - y is 44.
Solving the system of linear equations by elimination gives x=3x = 3 and y=1y = -1. Substituting these values into the target expression xyx - y yields 3(1)=3+1=43 - (-1) = 3 + 1 = 4.

Step-by-Step Solution

1
Eliminate one variable using the elimination method.
Multiply the first equation by 22 and the second equation by 33:
6x10y=286x - 10y = 28
6x+21y=36x + 21y = -3
Creating matching coefficients for xx allows elimination of xx by subtraction.
2
Subtract the first modified equation from the second modified equation to solve for yy.
(6x+21y)(6x10y)=328(6x + 21y) - (6x - 10y) = -3 - 28
31y=31    y=131y = -31 \implies y = -1
Subtracting eliminates xx, isolating yy.
3
Substitute y=1y = -1 back into one of the original equations to solve for xx.
3x5(1)=14    3x+5=14    3x=9    x=33x - 5(-1) = 14 \implies 3x + 5 = 14 \implies 3x = 9 \implies x = 3
Plugging in yy allows direct solution for xx.
4
Evaluate the requested expression xyx - y.
xy=3(1)=3+1=4x - y = 3 - (-1) = 3 + 1 = 4
Subtracting a negative value is equivalent to adding its positive value.

Key Concept

Solving systems of linear equations using elimination and evaluating algebraic expressions.
Estimated Time:1m 30s
Rate this question