Question

Difficulty: MediumEven-Odd Properties and Sign Rules

Let xx and yy be non-zero integers such that x5y2<0x^5 y^2 < 0 and x+yx + y is an odd integer. Which of the following statements MUST be true? Select all that apply.

  1. xx is a negative integerAnswer
  2. xyxy is an even integerAnswer
  3. x2+y2x^2 + y^2 is an odd integerAnswer
  4. D
    (x)y(-x)^y is guaranteed to be a positive integer
  5. E
    If x<yx < y, then x<y-x < -y

Answer

The statements 'xx is a negative integer', 'xyxy is an even integer', and 'x2+y2x^2 + y^2 is an odd integer' MUST be true.
The statement specifying that 'xx is a negative integer' is true because y2y^2 is strictly positive for any non-zero integer yy, forcing x5<0x^5 < 0 and thus x<0x < 0. The statement 'xyxy is an even integer' is true because x+yx + y being odd requires one variable to be even and the other to be odd, making their product even. The statement 'x2+y2x^2 + y^2 is an odd integer' is true because the square of an even number is even and the square of an odd number is odd, and their sum is always odd.

Step-by-Step Solution

1
Determine the sign of xx from the given inequality x5y2<0x^5 y^2 < 0.
xx must be negative (x<0x < 0).
Since yy is a non-zero integer, y2>0y^2 > 0. Dividing the inequality by y2y^2 gives x5<0x^5 < 0, which means xx must be negative.
2
Analyze the parity (even/odd nature) of xx and yy using x+yx + y is odd.
One of x,yx, y is even and the other is odd.
The sum of two integers is odd if and only if one integer is even and the other is odd.
3
Evaluate the statement 'xyxy is an even integer'.
The product xyxy is always even.
The product of an even integer and an odd integer is always even.
4
Evaluate the statement 'x2+y2x^2 + y^2 is an odd integer'.
The sum of squares x2+y2x^2 + y^2 is always odd.
Squaring an even integer yields an even integer, and squaring an odd integer yields an odd integer. Adding an even number and an odd number yields an odd number.

Key Concept

Even-Odd Parity Rules and Exponent Sign Properties
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