Question

Difficulty: EasyProbability of Independent, Dependent, and Mutually Exclusive Events

A box contains 44 red blocks and 66 yellow blocks. A block is selected at random from the box, its color is noted, and it is returned to the box. A second block is then selected at random from the box. What is the probability that both selected blocks are red?

  1. 425\frac{4}{25}Answer
  2. B
    215\frac{2}{15}
  3. C
    25\frac{2}{5}
  4. D
    49\frac{4}{9}
  5. E
    45\frac{4}{5}

Answer

The probability that both selected blocks are red is 425\frac{4}{25}.
Because the first block is returned to the box before the second selection, the two draws are independent events. The probability of selecting a red block on any single draw is 410=25\frac{4}{10} = \frac{2}{5}. Applying the multiplication rule for independent events gives P(Both red)=25×25=425P(\text{Both red}) = \frac{2}{5} \times \frac{2}{5} = \frac{4}{25}.

Step-by-Step Solution

1
Determine the total number of blocks in the box.
The total number of blocks is 4+6=104 + 6 = 10.
Probability requires finding the ratio of favorable outcomes to total possible outcomes.
2
Calculate the probability of drawing a red block on the first selection.
P(First is red)=410=25P(\text{First is red}) = \frac{4}{10} = \frac{2}{5}.
There are 44 red blocks out of 1010 total blocks.
3
Calculate the probability of drawing a red block on the second selection.
Since the first block is returned to the box, the events are independent, so P(Second is red)=410=25P(\text{Second is red}) = \frac{4}{10} = \frac{2}{5}.
Replacement preserves the original sample space composition.
4
Apply the multiplication rule for independent events.
P(Both are red)=P(First is red)×P(Second is red)=25×25=425P(\text{Both are red}) = P(\text{First is red}) \times P(\text{Second is red}) = \frac{2}{5} \times \frac{2}{5} = \frac{4}{25}.
The probability of two independent events both occurring is the product of their individual probabilities.

Key Concept

Probability of Independent Events
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