Question

Difficulty: EasySimultaneous Linear and Quadratic Equations

Find the positive value of xx that satisfies the simultaneous equations y2x=3y - 2x = 3 and y=x2+3y = x^2 + 3.

  1. 22Answer
  2. B
    2-2
  3. C
    33
  4. D
    55

Answer

The positive value of xx is 2.
Rearranging the linear equation gives y=2x+3y = 2x + 3. Setting this equal to the second expression for yy gives 2x+3=x2+32x + 3 = x^2 + 3, which simplifies to x22x=0x^2 - 2x = 0. Factoring out xx yields x(x2)=0x(x - 2) = 0. The solutions for xx are 00 and 22. The positive solution is 22.

Step-by-Step Solution

1
Express yy in terms of xx using the linear equation
y=2x+3y = 2x + 3
Isolating yy prepares for substitution into the quadratic equation.
2
Substitute y=2x+3y = 2x + 3 into the second equation y=x2+3y = x^2 + 3
2x+3=x2+32x + 3 = x^2 + 3
This creates a single quadratic equation in terms of xx.
3
Rearrange and factor the quadratic equation
x22x=0    x(x2)=0x^2 - 2x = 0 \implies x(x - 2) = 0
Subtracting 33 and 2x2x from both sides simplifies the equation to factorable form.
4
Solve for the non-zero (positive) value of xx
x=2x = 2
Setting x2=0x - 2 = 0 yields x=2x = 2.

Key Concept

Solving simultaneous linear and quadratic equations by substitution
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