Three isomeric alkanes have the molecular formula : pentane, 2-methylbutane, and 2,2-dimethylpropane. Which of the following statements correctly accounts for the trend in their boiling points?
- Pentane has the highest boiling point because its straight-chain structure provides a larger surface area for intermolecular van der Waals forces.Answer
- B2,2-Dimethylpropane has the highest boiling point because its compact spherical shape maximizes molecular interactions.
- C2-Methylbutane has a higher boiling point than pentane because branching increases the strength of intermolecular forces.
- DAll three isomers have identical boiling points because they possess the same molecular formula and molar mass.
Answer
Pentane has the highest boiling point because its straight-chain structure provides a larger surface area for intermolecular van der Waals forces.
Pentane possesses an unbranched, straight-chain hydrocarbon structure. This spatial arrangement allows adjacent molecules to lie close together with maximum surface contact. As a result, intermolecular van der Waals forces are strongest in pentane, requiring the highest temperature to transition from liquid to gas.
Step-by-Step Solution
Key Concept
Effect of structural branching on alkane boiling points and intermolecular forces
Estimated Time:1m 0s