Question

Difficulty: MediumMendel's First Law and Monohybrid Inheritance

In tomato plants, the allele for red fruit (RR) is completely dominant over the allele for yellow fruit (rr). If a heterozygous red-fruited plant is self-pollinated and produces 400400 offspring in the F2F_2 generation, how many of these plants are expected to be heterozygous red-fruited?

  1. 200200Answer
  2. B
    300300
  3. C
    100100
  4. D
    400400

Answer

The expected number of heterozygous red-fruited plants is 200.
Crossing two heterozygous individuals (Rr×RrRr \times Rr) produces genotypes in a 1 RR:2 Rr:1 rr1\ RR : 2\ Rr : 1\ rr ratio according to Mendel's First Law. Therefore, half (50%50\%) of the 400400 total offspring are expected to have the heterozygous genotype (RrRr), which equals 200200 plants.

Step-by-Step Solution

1
Determine the parental genotypes and set up the monohybrid cross.
The self-pollinated plant is heterozygous (RrRr), so the cross is Rr×RrRr \times Rr.
Mendel's First Law (Law of Segregation) states that paired alleles segregate during gamete formation so each gamete carries only one allele.
2
Calculate the genotypic ratio of the F2 generation.
The offspring genotypic ratio is 1 RR:2 Rr:1 rr1\ RR : 2\ Rr : 1\ rr, meaning 1/41/4 homozygous dominant, 2/42/4 (or 1/21/2) heterozygous, and 1/41/4 homozygous recessive.
Random combination of parental gametes (RR and rr) yields probabilities of 25% RR25\%\ RR, 50% Rr50\%\ Rr, and 25% rr25\%\ rr.
3
Compute the expected count of heterozygous offspring out of 400 total plants.
Heterozygous count = 24×400=200\frac{2}{4} \times 400 = 200 plants.
Multiplying the probability of the heterozygous genotype (1/21/2) by the total number of offspring gives the expected number.

Key Concept

Mendel's Law of Segregation and Monohybrid Genotypic Ratios
Rate this question