Question

Difficulty: Very hardMendel's First Law and Monohybrid Inheritance

In sorghum plants, tall stem height (TT) is completely dominant over dwarf stem height (tt). In a monohybrid cross between two heterozygous tall plants (Tt×TtTt \times Tt), the conditional probability that a plant displaying the tall phenotype is homozygous dominant (TTTT) is 1/31/3.

Answer: Answer

Answer

The statement is true because restricting the sample space to offspring displaying the dominant tall phenotype (TTTT and TtTt) yields 3 out of 4 total genotypic combinations, of which exactly 1 is homozygous dominant (TTTT), giving a conditional probability of 1/31/3.
The statement is correct because out of the 3 possible genotype combinations that produce the dominant tall phenotype (1 TT1\ TT and 2 Tt2\ Tt), exactly 1 is homozygous dominant (TTTT), making the conditional probability 1/31/3.

Step-by-Step Solution

1
Determine the genotypic ratio resulting from a monohybrid cross of two heterozygotes (Tt×TtTt \times Tt).
The genotypic ratio is 1 TT:2 Tt:1 tt1\ TT : 2\ Tt : 1\ tt.
According to Mendel's Law of Segregation, alleles segregate independently during gamete formation, resulting in a 1:2:11:2:1 genotypic ratio.
2
Identify the genotypes that express the dominant tall phenotype.
Tall plants possess either the homozygous dominant genotype (TTTT) or the heterozygous genotype (TtTt), totaling 33 out of 44 genotypic units (1 TT+2 Tt1\ TT + 2\ Tt).
Dominance dictates that both TTTT and TtTt produce the tall phenotype.
3
Calculate the conditional probability that a tall plant is homozygous dominant (TTTT).
The probability is Number of TT combinationsTotal number of tall combinations=11+2=13\frac{\text{Number of } TT \text{ combinations}}{\text{Total number of tall combinations}} = \frac{1}{1 + 2} = \frac{1}{3}.
The question restricts the sample space to only tall offspring.

Key Concept

Conditional probability in monohybrid crosses and Mendel's Law of Segregation
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