Question

Difficulty: MediumIndefinite Integration of Polynomial and Trigonometric Functions

What is the indefinite integral (3x25sin(5x)+2)dx\int (3x^2 - 5\sin(5x) + 2) \, dx?

  1. x3+cos(5x)+2x+Cx^3 + \cos(5x) + 2x + CAnswer
  2. B
    x3cos(5x)+2x+Cx^3 - \cos(5x) + 2x + C
  3. C
    x3+25cos(5x)+2x+Cx^3 + 25\cos(5x) + 2x + C
  4. D
    x3+cos(5x)+2xx^3 + \cos(5x) + 2x

Answer

x3+cos(5x)+2x+Cx^3 + \cos(5x) + 2x + C
Integrating term-by-term yields 3x2dx=x3\int 3x^2 dx = x^3, 5sin(5x)dx=cos(5x)\int -5\sin(5x) dx = \cos(5x), and 2dx=2x\int 2 dx = 2x. Adding the arbitrary constant CC produces x3+cos(5x)+2x+Cx^3 + \cos(5x) + 2x + C.

Step-by-Step Solution

1
Integrate the polynomial term 3x23x^2 using the power rule xndx=xn+1n+1\int x^n dx = \frac{x^{n+1}}{n+1}
3x2dx=3x33=x3\int 3x^2 dx = 3 \cdot \frac{x^3}{3} = x^3
Applying the power rule for integration.
2
Integrate the trigonometric term 5sin(5x)-5\sin(5x) using sin(kx)dx=1kcos(kx)\int \sin(kx) dx = -\frac{1}{k}\cos(kx)
5sin(5x)dx=5(15cos(5x))=cos(5x)\int -5\sin(5x) dx = -5 \left(-\frac{1}{5}\cos(5x)\right) = \cos(5x)
Integration of the sine function reverses differentiation with a positive sign change for negative sine.
3
Integrate the constant term 22 and append the constant of integration CC
2dx=2x\int 2 dx = 2x, giving total antiderivative x3+cos(5x)+2x+Cx^3 + \cos(5x) + 2x + C
Indefinite integrals always require an arbitrary constant of integration CC.

Key Concept

Indefinite Integration of Polynomial and Trigonometric Functions
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