Question

Difficulty: EasyDifferentiation of Trigonometric, Exponential, and Logarithmic Functions

If y=e4x−sin⁡xy = e^{4x} - \sin x, what is dydx\frac{dy}{dx}?

  1. 4e4x−cos⁡x4e^{4x} - \cos xAnswer
  2. B
    4e4x+cos⁡x4e^{4x} + \cos x
  3. C
    e4x−cos⁡xe^{4x} - \cos x
  4. D
    e4x+cos⁡xe^{4x} + \cos x

Answer

4e4x−cos⁡x4e^{4x} - \cos x
Differentiating e4xe^{4x} gives 4e4x4e^{4x} by applying the chain rule, and differentiating −sin⁡x-\sin x yields −cos⁡x-\cos x. Combining these terms gives the correct derivative 4e4x−cos⁡x4e^{4x} - \cos x.

Step-by-Step Solution

1
Apply the sum/difference rule of differentiation.
\frac{dy}{dx} = \frac{d}{dx}(e^{4x}) - \frac{d}{dx}(\sin x)
The derivative of a difference of two terms is the difference of their individual derivatives.
2
Differentiate the exponential term e4xe^{4x} using the chain rule.
ddx(e4x)=4e4x\frac{d}{dx}(e^{4x}) = 4e^{4x}
By the chain rule, \frac{d}{dx}(e^{k x}) = k e^{k x}.
3
Differentiate the trigonometric term sin⁡x\sin x.
ddx(sin⁡x)=cos⁡x\frac{d}{dx}(\sin x) = \cos x
The standard derivative of sin⁡x\sin x with respect to xx is cos⁡x\cos x.
4
Combine the results.
\frac{dy}{dx} = 4e^{4x} - \cos x
Subtracting the derivative of sin⁡x\sin x from the derivative of e4xe^{4x} gives the final answer.

Key Concept

Differentiation of Exponential and Trigonometric Functions
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