Although fluorine and chlorine are both Group 17 halogens, hydrogen fluoride () exhibits intermolecular hydrogen bonding in the liquid state while hydrogen chloride () does not. Which of the following statements best accounts for this difference?
- Fluorine has a higher electronegativity and smaller atomic radius than chlorine, creating a highly polar bond.Answer
- BThe intramolecular covalent bond in an molecule is weaker than the covalent bond in an molecule.
- CHydrogen fluoride has a greater molar mass than hydrogen chloride, generating stronger dispersion forces.
- DChlorine is more electronegative than fluorine, causing molecules to experience non-polar interactions.
Answer
Fluorine's high electronegativity combined with its small atomic size allows for strong electrostatic attraction between the hydrogen atom of one molecule and the lone pair on the fluorine atom of an adjacent molecule.
Hydrogen bonding requires hydrogen to be covalently attached to a very small, highly electronegative atom (N, O, or F). Fluorine fulfills both conditions, giving the bond a large dipole moment and high localized charge density that attracts adjacent molecules strongly.
Step-by-Step Solution
Key Concept
Intermolecular Forces and Hydrogen Bonding
Estimated Time:1m 0s