A solid block of wood has a mass of 0.60\text{ kg}. When placed in a vessel of water, it f… — JAMB UTME

A solid block of wood has a mass of $0.60\text{ kg}$ . When placed in a vessel of water, it floats freely on the surface. What is the magnitude of the upthrust exerted by the water on the block? (Take $g = 10\text{ m/s}^2$ )

$6.0\text{ N}$ Answer
B
$0.60\text{ N}$
C
$0.0\text{ N}$
D
$60\text{ N}$

Answer

The upthrust exerted by the water on the floating block is

6.0\text{ N}

According to the Law of Flotation, a body floating freely in a fluid displaces a weight of fluid equal to its own weight. Therefore, the upward force (upthrust) exerted by the fluid is equal to the weight of the block:

U = mg = 0.60\text{ kg} \times 10\text{ m/s}^2 = 6.0\text{ N}

Step-by-Step Solution

Determine the weight of the floating block in air.

W = mg = 0.60\text{ kg} \times 10\text{ m/s}^2 = 6.0\text{ N}

Weight is the force of gravity acting on the block's mass.

Apply the Law of Flotation to find the upthrust.

Upthrust

U = W = 6.0\text{ N}

A freely floating body displaces a volume of fluid whose weight is equal to the total weight of the body.

Key Concept

Law of Flotation and Archimedes' Principle

Estimated Time:45s

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