Question

Difficulty: MediumBasic Trigonometric Ratios, Special Angles, and Identities

What is the exact numerical value of the trigonometric expression 4cos230+2sin245tan260csc30\frac{4\cos^2 30^\circ + 2\sin^2 45^\circ}{\tan^2 60^\circ - \csc 30^\circ}?

Answer: 4

Answer

4
By evaluating the special angles directly: 4cos230=34\cos^2 30^\circ = 3, 2sin245=12\sin^2 45^\circ = 1, tan260=3\tan^2 60^\circ = 3, and csc30=2\csc 30^\circ = 2. Substituting these into the expression yields 3+132=41=4\frac{3 + 1}{3 - 2} = \frac{4}{1} = 4.

Step-by-Step Solution

1
Substitute the exact value of cos30\cos 30^\circ
4cos230=4(32)2=4(34)=34\cos^2 30^\circ = 4 \left(\frac{\sqrt{3}}{2}\right)^2 = 4 \left(\frac{3}{4}\right) = 3
The exact value of cos30\cos 30^\circ is 32\frac{\sqrt{3}}{2}.
2
Substitute the exact value of sin45\sin 45^\circ
2sin245=2(12)2=2(12)=12\sin^2 45^\circ = 2 \left(\frac{1}{\sqrt{2}}\right)^2 = 2 \left(\frac{1}{2}\right) = 1
The exact value of sin45\sin 45^\circ is 12\frac{1}{\sqrt{2}}.
3
Substitute the exact values of tan60\tan 60^\circ and csc30\csc 30^\circ
tan260=(3)2=3\tan^2 60^\circ = (\sqrt{3})^2 = 3 and csc30=1sin30=2\csc 30^\circ = \frac{1}{\sin 30^\circ} = 2
The exact value of tan60\tan 60^\circ is 3\sqrt{3} and csc30\csc 30^\circ is the reciprocal of sin30=12\sin 30^\circ = \frac{1}{2}.
4
Simplify the entire fraction
3+132=41=4\frac{3 + 1}{3 - 2} = \frac{4}{1} = 4
Dividing the simplified numerator (4) by the simplified denominator (1) gives 4.

Key Concept

Evaluation of Special Angle Trigonometric Ratios and Reciprocal Functions
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