Question

Difficulty: MediumSubatomic Particles, Atomic Number, Mass Number, and Isotopy

A naturally occurring sample of neon gas consists of 90%90\% 20Ne^{20}\text{Ne} and 10%10\% 22Ne^{22}\text{Ne}. What is the relative atomic mass of neon in this sample?

Answer: 20.2

Answer

The relative atomic mass of neon in the sample is 20.2.
The relative atomic mass of an element is calculated by summing the products of the mass number of each isotope and its fractional abundance: RAM=(20×0.90)+(22×0.10)=18.0+2.2=20.2\text{RAM} = (20 \times 0.90) + (22 \times 0.10) = 18.0 + 2.2 = 20.2.

Step-by-Step Solution

1
Calculate the weighted contribution of 20Ne^{20}\text{Ne}
20×0.90=18.020 \times 0.90 = 18.0
The isotope 20Ne^{20}\text{Ne} accounts for 90%90\% of the sample.
2
Calculate the weighted contribution of 22Ne^{22}\text{Ne}
22×0.10=2.222 \times 0.10 = 2.2
The isotope 22Ne^{22}\text{Ne} accounts for 10%10\% of the sample.
3
Sum the weighted contributions to find the relative atomic mass
18.0+2.2=20.218.0 + 2.2 = 20.2
The relative atomic mass is the weighted average of the atomic masses of naturally occurring isotopes.

Key Concept

Calculation of Relative Atomic Mass from Isotopic Abundance
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