Question

Difficulty: MediumSubatomic Particles, Atomic Number, Mass Number, and Isotopy

Element QQ occurs naturally as two isotopes, 35Q^{35}Q and 37Q^{37}Q. If the relative atomic mass of element QQ is 35.535.5, what is the percentage abundance of the heavier isotope 37Q^{37}Q?

  1. 25%Answer
  2. B
    75%
  3. C
    50%
  4. D
    35.5%

Answer

The percentage abundance of 37Q^{37}Q is 25%.
The relative atomic mass (35.535.5) lies between 3535 and 3737, closer to 3535. Setting up the weighted average equation 35.5=35(100x)+37x10035.5 = \frac{35(100 - x) + 37x}{100} yields x=25%x = 25\% for 37Q^{37}Q, while 35Q^{35}Q accounts for the remaining 75%75\%.

Step-by-Step Solution

1
Set up the relative atomic mass equation using percentage abundances.
Let the percentage abundance of 37Q^{37}Q be x%x\%. Therefore, the abundance of 35Q^{35}Q is (100x)%(100 - x)\%.
The sum of natural abundances for all isotopes of an element must equal 100%.
2
Substitute the isotopic mass numbers and relative atomic mass into the weighted average formula.
35.5=35(100x)+37x10035.5 = \frac{35(100 - x) + 37x}{100}
Relative atomic mass is calculated as the weighted average of the mass numbers of naturally occurring isotopes.
3
Solve the linear equation for xx.
3550=350035x+37x    50=2x    x=253550 = 3500 - 35x + 37x \implies 50 = 2x \implies x = 25
Multiplying by 100 and rearranging terms isolates x=25x = 25.

Key Concept

Calculation of isotopic abundances from relative atomic mass
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