Question

Difficulty: EasyEmpirical and Molecular Formula Calculations

A compound has an empirical formula of CH2CH_2 and a relative molecular mass of 4242. What is the molecular formula of the compound? [C=12,H=1][C = 12, H = 1]

  1. C3H6C_3H_6Answer
  2. B
    C2H4C_2H_4
  3. C
    C4H8C_4H_8
  4. D
    CH2CH_2

Answer

The molecular formula of the compound is C3H6C_3H_6.
The empirical formula mass of CH2CH_2 is 14 g/mol14\text{ g/mol}. Dividing the given relative molecular mass (4242) by 1414 gives an integer factor n=3n = 3. Multiplying the empirical formula indices by 33 gives C3H6C_3H_6.

Step-by-Step Solution

1
Calculate the empirical formula mass of CH2CH_2.
Empirical formula mass =12+2(1)=14 g/mol= 12 + 2(1) = 14\text{ g/mol}.
The empirical formula mass is required to find the integer ratio multiplier nn.
2
Determine the integer multiplier nn by dividing the relative molecular mass by the empirical formula mass.
n=4214=3n = \frac{42}{14} = 3.
The integer multiplier indicates how many empirical units constitute the molecular formula.
3
Multiply the subscripts of the empirical formula CH2CH_2 by n=3n = 3.
Molecular formula =(CH2)3=C3H6= (CH_2)_3 = C_3H_6.
Applying the integer multiplier yields the true formula of the compound.

Key Concept

Molecular Formula Derivation from Empirical Formula and Molar Mass
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