Question

Difficulty: HardEmpirical and Molecular Formula Calculations

An organic compound containing carbon, hydrogen, and nitrogen was analyzed and found to contain 61.02%61.02\% carbon and 15.25%15.25\% hydrogen by mass, with the remainder being nitrogen. Given that the relative molecular mass of the compound is 118 g/mol118\text{ g/mol}, what is the value of the integer multiplier nn that relates its empirical formula to its molecular formula? [C=12,H=1,N=14][C = 12, H = 1, N = 14]

Answer: 2

Answer

The value of the integer multiplier n is 2.
Subtracting the carbon (61.02%61.02\%) and hydrogen (15.25%15.25\%) percentages from 100%100\% gives a nitrogen content of 23.73%23.73\%. Converting these mass percentages to mole ratios by dividing by relative atomic masses (C=12,H=1,N=14C=12, H=1, N=14) gives 5.085 mol5.085\text{ mol} of C, 15.25 mol15.25\text{ mol} of H, and 1.695 mol1.695\text{ mol} of N. Dividing by the smallest value (1.6951.695) produces the mole ratio 3:9:13:9:1, establishing the empirical formula as C3H9NC_3H_9N. The empirical mass is (3×12)+(9×1)+14=59 g/mol(3 \times 12) + (9 \times 1) + 14 = 59\text{ g/mol}. Dividing the relative molecular mass (118 g/mol118\text{ g/mol}) by the empirical mass (59 g/mol59\text{ g/mol}) yields n=2n = 2.

Step-by-Step Solution

1
Calculate percentage composition of nitrogen
23.73%
The sum of percentages of all constituent elements in a compound must equal 100%.
2
Calculate relative number of moles for each element
C = 5.085 mol, H = 15.25 mol, N = 1.695 mol
Dividing the mass percentage of each element by its relative atomic mass gives its relative mole quantity.
3
Determine simplest whole number atomic ratio
C : H : N = 3 : 9 : 1
Dividing all mole amounts by the smallest value (1.695) gives the empirical mole ratio.
4
Determine the empirical formula mass
59 g/mol
Summing the atomic masses of elements in C3H9N yields (3 x 12) + (9 x 1) + 14 = 59 g/mol.
5
Calculate the integer multiplier n
2
Dividing relative molecular mass (118 g/mol) by empirical formula mass (59 g/mol) gives n = 2.

Key Concept

Calculation of Empirical Formula and Molecular Formula Multiplier
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