Question

Difficulty: MediumIndefinite Integration of Polynomial and Trigonometric Functions

If (8x39sin(3x)+2)dx=ax4+bcos(3x)+cx+C\int (8x^3 - 9\sin(3x) + 2) \, dx = ax^4 + b\cos(3x) + cx + C, where aa, bb, and cc are constant coefficients and CC is the constant of integration, what is the value of a+b+ca + b + c?

Answer: 7

Answer

The value of a+b+ca + b + c is 7.
Integrating term-by-term yields 8x3dx=2x4\int 8x^3 dx = 2x^4, 9sin(3x)dx=3cos(3x)\int -9\sin(3x) dx = 3\cos(3x), and 2dx=2x\int 2 dx = 2x. Equating coefficients with ax4+bcos(3x)+cxax^4 + b\cos(3x) + cx gives a=2a = 2, b=3b = 3, and c=2c = 2. Therefore, a+b+c=2+3+2=7a + b + c = 2 + 3 + 2 = 7.

Step-by-Step Solution

1
Integrate the polynomial term 8x38x^3
8x3dx=2x4\int 8x^3 \, dx = 2x^4, identifying a=2a = 2
Apply the power rule of integration: xndx=xn+1n+1\int x^n \, dx = \frac{x^{n+1}}{n+1}.
2
Integrate the trigonometric term 9sin(3x)-9\sin(3x)
9sin(3x)dx=3cos(3x)\int -9\sin(3x) \, dx = 3\cos(3x), identifying b=3b = 3
Apply the standard trigonometric integral formula: sin(kx)dx=1kcos(kx)\int \sin(kx) \, dx = -\frac{1}{k}\cos(kx).
3
Integrate the constant term 22
2dx=2x\int 2 \, dx = 2x, identifying c=2c = 2
The integral of a constant kk with respect to xx is kxkx.
4
Calculate the requested sum a+b+ca + b + c
a+b+c=2+3+2=7a + b + c = 2 + 3 + 2 = 7
Summing the coefficients derived from each term's antiderivative.

Key Concept

Indefinite Integration of Polynomial and Trigonometric Functions
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