Question

Difficulty: MediumActivation Energy and Energy Profile Diagrams

For the endothermic gaseous reaction PCl5(g)PCl3(g)+Cl2(g)\text{PCl}_5(g) \rightarrow \text{PCl}_3(g) + \text{Cl}_2(g), the standard enthalpy change (ΔH\Delta H) is +92 kJ mol1+92\text{ kJ mol}^{-1}. The activation energy for the reverse reaction without a catalyst is 58 kJ mol158\text{ kJ mol}^{-1}. If a catalyst is introduced that lowers the activation energy of the forward reaction by 35 kJ mol135\text{ kJ mol}^{-1}, what is the activation energy for the catalyzed forward reaction in kJ mol1\text{kJ mol}^{-1}?

Answer: 115 kJ mol^{-1}

Answer

The activation energy for the catalyzed forward reaction is 115 kJ mol1115\text{ kJ mol}^{-1}.
For an endothermic reaction, the enthalpy change is the difference between the forward and reverse activation energies: ΔH=Ea,forwardEa,reverse\Delta H = E_{a,\text{forward}} - E_{a,\text{reverse}}. Rearranging gives the uncatalyzed forward activation energy as 92 kJ mol1+58 kJ mol1=150 kJ mol192\text{ kJ mol}^{-1} + 58\text{ kJ mol}^{-1} = 150\text{ kJ mol}^{-1}. A catalyst lowers the activation energy by 35 kJ mol135\text{ kJ mol}^{-1}, resulting in a catalyzed forward activation energy of 150 kJ mol135 kJ mol1=115 kJ mol1150\text{ kJ mol}^{-1} - 35\text{ kJ mol}^{-1} = 115\text{ kJ mol}^{-1}.

Step-by-Step Solution

1
Determine the activation energy of the uncatalyzed forward reaction
Ea,forward, uncatalyzed=150 kJ mol1E_{a,\text{forward, uncatalyzed}} = 150\text{ kJ mol}^{-1}
For an endothermic reaction, ΔH=Ea,forwardEa,reverse\Delta H = E_{a,\text{forward}} - E_{a,\text{reverse}}. Substituting ΔH=+92 kJ mol1\Delta H = +92\text{ kJ mol}^{-1} and Ea,reverse=58 kJ mol1E_{a,\text{reverse}} = 58\text{ kJ mol}^{-1} gives Ea,forward, uncatalyzed=92+58=150 kJ mol1E_{a,\text{forward, uncatalyzed}} = 92 + 58 = 150\text{ kJ mol}^{-1}.
2
Apply the effect of the catalyst on the forward activation energy
Ea,forward, catalyzed=115 kJ mol1E_{a,\text{forward, catalyzed}} = 115\text{ kJ mol}^{-1}
The catalyst lowers the energy barrier for the forward reaction by 35 kJ mol135\text{ kJ mol}^{-1}, so Ea,forward, catalyzed=15035=115 kJ mol1E_{a,\text{forward, catalyzed}} = 150 - 35 = 115\text{ kJ mol}^{-1}.

Key Concept

Calculation of activation energy for catalyzed and uncatalyzed reactions using enthalpy change and reverse activation energy on an energy profile.
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