Question

Difficulty: MediumPolynomials, Factor and Remainder Theorems

Given that (x+2)(x + 2) is a factor of the polynomial P(x)=2x3x2+ax+bP(x) = 2x^3 - x^2 + ax + b, and that dividing P(x)P(x) by (2x1)(2x - 1) leaves a remainder of 1515, what is the value of a+ba + b?

  1. A
    66
  2. B
    1111
  3. 1414Answer
  4. D
    1-1

Answer

The value of a+ba + b is 1414.
Applying the Factor Theorem with x=2x = -2 gives the equation 2a+b=20-2a + b = 20. Applying the Remainder Theorem with x=12x = \frac{1}{2} gives the equation a+2b=30a + 2b = 30. Solving these simultaneous equations yields a=2a = -2 and b=16b = 16. Adding aa and bb gives 1414.

Step-by-Step Solution

1
Apply the Factor Theorem for (x+2)(x + 2)
2a+b=20-2a + b = 20
Since (x+2)(x + 2) is a factor of P(x)P(x), P(2)=0P(-2) = 0. Substituting x=2x = -2 yields 2(2)3(2)2+a(2)+b=02(-2)^3 - (-2)^2 + a(-2) + b = 0, which simplifies to 1642a+b=0-16 - 4 - 2a + b = 0 or 2a+b=20-2a + b = 20.
2
Apply the Remainder Theorem for (2x1)(2x - 1)
a+2b=30a + 2b = 30
Dividing P(x)P(x) by (2x1)(2x - 1) leaves a remainder of 1515, so P(12)=15P\left(\frac{1}{2}\right) = 15. Substituting x=12x = \frac{1}{2} yields 2(18)14+a2+b=152\left(\frac{1}{8}\right) - \frac{1}{4} + \frac{a}{2} + b = 15, which simplifies to a2+b=15\frac{a}{2} + b = 15 or a+2b=30a + 2b = 30.
3
Solve the system of linear equations for aa and bb
a=2a = -2 and b=16b = 16
From step 1, b=2a+20b = 2a + 20. Substituting this into step 2 gives a+2(2a+20)=30    5a+40=30    5a=10    a=2a + 2(2a + 20) = 30 \implies 5a + 40 = 30 \implies 5a = -10 \implies a = -2. Substituting a=2a = -2 into b=2a+20b = 2a + 20 gives b=16b = 16.
4
Calculate a+ba + b
1414
Summing the calculated values gives a+b=2+16=14a + b = -2 + 16 = 14.

Key Concept

Factor Theorem and Remainder Theorem for Polynomials
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