In fruit flies (*Drosophila melanogaster*), grey body color () is dominant over black body color (), and normal wing length () is dominant over vestigial wings (). If two heterozygous grey-bodied, normal-winged flies () are crossed and produce a total of 320 offspring, how many of these offspring are expected to exhibit a black body with normal wings?
- 60Answer
- B180
- C20
- D240
Answer
60 offspring are expected to have a black body with normal wings.
In a dihybrid cross of two heterozygous individuals (), the independent assortment of alleles yields an F2 phenotypic ratio of . The proportion of offspring displaying the recessive trait for the first gene (black body, ) and the dominant trait for the second gene (normal wings, ) is . Multiplying by the total offspring count of gives exactly .
Step-by-Step Solution
Key Concept
Mendel's Law of Independent Assortment and Dihybrid Phenotypic Ratios
Estimated Time:1m 30s