When an unknown alkanol is warmed with acidified potassium heptaoxodichromate(VI) () solution, the orange solution turns green and an alkanone is produced. Which of the following compounds undergoes this reaction?
- Propan-2-olAnswer
- BPropan-1-ol
- C2-Methylpropan-2-ol
- DEthanol
Answer
Propan-2-ol is a secondary alkanol that undergoes oxidation to form an alkanone (propanone), changing the color of acidified potassium heptaoxodichromate(VI) from orange to green.
Propan-2-ol is a secondary alkanol (). Upon oxidation with acidified , the orange dichromate(VI) ions () are reduced to green chromium(III) ions (), and the secondary alcohol is converted into propanone (), which belongs to the alkanone family.
Step-by-Step Solution
Key Concept
Oxidation of Alkanols (Primary, Secondary, and Tertiary Classification)
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