Question

Difficulty: EasyBinary Operations

A binary operation \ast defined on the set of real numbers R\mathbb{R} is given by ab=a+b+7a \ast b = a + b + 7. What is the identity element under this operation?

Answer: -7

Answer

The identity element under the operation is 7-7.
The identity element ee satisfies ae=aa \ast e = a for any real number aa. Substituting into the definition gives a+e+7=aa + e + 7 = a, which simplifies to e=7e = -7.

Step-by-Step Solution

1
Set up the identity element equation using the definition ae=aa \ast e = a.
a+e+7=aa + e + 7 = a
By definition, operating any element aa with the identity element ee yields aa.
2
Subtract aa from both sides of the equation.
e+7=0e + 7 = 0
Isolating terms involving ee.
3
Subtract 77 from both sides to solve for ee.
e=7e = -7
Determining the numerical value of the identity element.

Key Concept

Identity Element in Binary Operations
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