Question

Difficulty: MediumSimultaneous Linear and Quadratic Equations

What is the sum of the yy-values of the solution pairs that satisfy the simultaneous equations yx=2y - x = 2 and y=x23x+5y = x^2 - 3x + 5?

  1. A
    44
  2. B
    66
  3. 88Answer
  4. D
    1515

Answer

The sum of the yy-values is 8.
Rearranging the linear equation gives y=x+2y = x + 2. Equating this to the quadratic expression gives x+2=x23x+5x + 2 = x^2 - 3x + 5, which simplifies to x24x+3=0x^2 - 4x + 3 = 0. Solving for xx yields x=1x = 1 and x=3x = 3. Substituting these into y=x+2y = x + 2 gives y=3y = 3 and y=5y = 5. The sum of these yy-values is 3+5=83 + 5 = 8.

Step-by-Step Solution

1
Express yy in terms of xx from the linear equation.
y=x+2y = x + 2
Isolating yy facilitates substitution into the quadratic equation.
2
Substitute y=x+2y = x + 2 into the quadratic equation and rearrange into standard form.
x+2=x23x+5    x24x+3=0x + 2 = x^2 - 3x + 5 \implies x^2 - 4x + 3 = 0
Setting the two expressions for yy equal to each other forms a single quadratic equation in xx.
3
Solve the quadratic equation for xx.
(x1)(x3)=0    x1=1,x2=3(x - 1)(x - 3) = 0 \implies x_1 = 1, x_2 = 3
Factoring gives the xx-coordinates of the intersection points.
4
Calculate the corresponding yy-values using y=x+2y = x + 2.
y1=1+2=3y_1 = 1 + 2 = 3 and y2=3+2=5y_2 = 3 + 2 = 5
Each xx-value must be substituted into the linear equation to find its paired yy-value.
5
Find the sum of the yy-values.
y1+y2=3+5=8y_1 + y_2 = 3 + 5 = 8
The question asks for the sum of the yy-coordinates.

Key Concept

Simultaneous Linear and Quadratic Equations

Alternative Method

Using Vieta's formulas: once the quadratic equation for xx is found as x24x+3=0x^2 - 4x + 3 = 0, we know x1+x2=4x_1 + x_2 = 4. Since y1=x1+2y_1 = x_1 + 2 and y2=x2+2y_2 = x_2 + 2, the sum of the yy-values is y1+y2=(x1+2)+(x2+2)=(x1+x2)+4=4+4=8y_1 + y_2 = (x_1 + 2) + (x_2 + 2) = (x_1 + x_2) + 4 = 4 + 4 = 8.
Estimated Time:1m 30s
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