Question

Difficulty: EasySimultaneous Linear and Quadratic Equations

What is the positive value of xx that satisfies the simultaneous equations yx=1y - x = 1 and y=x25y = x^2 - 5?

  1. A
    22
  2. 33Answer
  3. C
    44
  4. D
    55

Answer

The positive value of xx is 33.
Substituting y=x+1y = x + 1 from the linear equation into the quadratic equation gives x+1=x25x + 1 = x^2 - 5. Rearranging terms yields x2x6=0x^2 - x - 6 = 0, which factors as (x3)(x+2)=0(x - 3)(x + 2) = 0. The roots are x=3x = 3 and x=2x = -2. Selecting the positive solution gives 33.

Step-by-Step Solution

1
Express yy in terms of xx using the linear equation.
y=x+1y = x + 1
Isolating yy simplifies substitution into the quadratic equation.
2
Substitute y=x+1y = x + 1 into the quadratic equation y=x25y = x^2 - 5.
x+1=x25x + 1 = x^2 - 5
This produces a quadratic equation in one variable, xx.
3
Rearrange into standard quadratic form ax2+bx+c=0ax^2 + bx + c = 0.
x2x6=0x^2 - x - 6 = 0
Standard quadratic form allows direct factorization.
4
Factorize the quadratic equation.
(x3)(x+2)=0(x - 3)(x + 2) = 0
Factoring determines the roots of the equation.
5
Solve for xx and identify the positive value.
x=3x = 3 or x=2x = -2; positive value is 33.
The question specifies the positive real solution for xx.

Key Concept

Solving simultaneous linear and quadratic equations using substitution
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