Question

Difficulty: HardMeasures of Central Tendency for Grouped Data

The operating lifespans (in hours) of a sample of 6060 newly manufactured micro-components tested under laboratory conditions are presented in the frequency table below:

Lifespan (hours)Frequency (ff)
101910 - 1955
202920 - 2988
303930 - 391212
404940 - 492020
505950 - 591515

Using linear interpolation on class boundaries, calculate the median lifespan of the components in hours.

Answer: 42 hours

Answer

The median lifespan of the micro-components is 42 hours.
To calculate the median of grouped data, first determine cumulative frequencies: 5, 13, 25, 45, 60. Total frequency is N=60N = 60, placing the median at N/2=30N/2 = 30. The median class is 404940 - 49 with lower class boundary L=39.5L = 39.5, class frequency f=20f = 20, cumulative frequency prior to median class c.f.=25c.f. = 25, and class width c=10c = 10. Substituting into Median=L+(N/2c.f.f)×c\text{Median} = L + \left(\frac{N/2 - c.f.}{f}\right) \times c gives 39.5+(302520)×10=39.5+2.5=4239.5 + \left(\frac{30 - 25}{20}\right) \times 10 = 39.5 + 2.5 = 42.

Step-by-Step Solution

1
Calculate the total frequency NN and the median rank N/2N/2.
N=5+8+12+20+15=60N = 5 + 8 + 12 + 20 + 15 = 60, so N/2=30N/2 = 30.
The median corresponds to the value at position 30 in the ordered cumulative frequency distribution.
2
Determine cumulative frequencies to locate the median class.
Cumulative frequencies are 5, 13, 25, 45, 60. The 30th value falls in the interval 404940 - 49.
The cumulative frequency first reaches or exceeds 30 at the 404940 - 49 class.
3
Identify boundary parameters for the median class.
Lower boundary L=39.5L = 39.5, class width c=10c = 10, class frequency f=20f = 20, and cumulative frequency of preceding class c.f.=25c.f. = 25.
Continuous data analysis requires using lower class boundaries rather than class limits.
4
Apply the grouped median linear interpolation formula.
Median=39.5+(302520)×10=39.5+2.5=42\text{Median} = 39.5 + \left(\frac{30 - 25}{20}\right) \times 10 = 39.5 + 2.5 = 42.
Linear interpolation within the median class yields the precise median value.

Key Concept

Grouped Data Median via Class Boundary Interpolation
Estimated Time:2m 0s
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