Question

Difficulty: HardNatural Radioactivity and Radiation Emissions

A heavy radioactive parent nucleus undergoes a decay series emitting five α\alpha-particles and four β\beta^{-}-particles to form a stable daughter nucleus. What is the net change in the mass number (AA) and atomic number (ZZ) of the nucleus?

  1. Mass number decreases by 2020, and atomic number decreases by 66Answer
  2. B
    Mass number decreases by 2020, and atomic number decreases by 1414
  3. C
    Mass number decreases by 99, and atomic number decreases by 66
  4. D
    Mass number decreases by 2020, and atomic number decreases by 1010

Answer

The mass number decreases by 2020, and the atomic number decreases by 66.
An alpha particle emission removes 2 protons and 2 neutrons (24He^{4}_{2}\text{He}), reducing the atomic mass number by 4 and the atomic number by 2. Five alpha emissions reduce AA by 2020 and ZZ by 1010. A beta-minus emission (10e^{0}_{-1}e) converts a neutron into a proton, leaving AA unchanged while increasing ZZ by 1. Four beta-minus emissions increase ZZ by 4. Combining these gives a net decrease in mass number of 20 and a net decrease in atomic number of 6.

Step-by-Step Solution

1
Determine the change in mass number (AA) and atomic number (ZZ) due to α\alpha-emissions.
Each α\alpha-particle (24He^{4}_{2}\text{He}) decreases AA by 44 and ZZ by 22. For 55 α\alpha-particles: ΔAα=5×(4)=20\Delta A_{\alpha} = 5 \times (-4) = -20, ΔZα=5×(2)=10\Delta Z_{\alpha} = 5 \times (-2) = -10.
Alpha particles consist of two protons and two neutrons.
2
Determine the change in mass number (AA) and atomic number (ZZ) due to β\beta^{-}-emissions.
Each β\beta^{-}-particle (10e^{0}_{-1}e) leaves AA unchanged and increases ZZ by 11. For 44 β\beta^{-}-particles: ΔAβ=0\Delta A_{\beta} = 0, ΔZβ=4×(+1)=+4\Delta Z_{\beta} = 4 \times (+1) = +4.
Beta-minus decay involves a neutron converting into a proton, emitting an electron.
3
Sum the total changes for AA and ZZ.
Net ΔA=20+0=20\Delta A = -20 + 0 = -20 (decrease by 2020). Net ΔZ=10+4=6\Delta Z = -10 + 4 = -6 (decrease by 66).
Combining independent particle emission effects yields the total net change.

Key Concept

Natural radioactive radiation emissions change nuclear composition: alpha emission (24He^{4}_{2}\text{He}) reduces AA by 44 and ZZ by 22, whereas beta-minus emission (10e^{0}_{-1}e) keeps AA constant and increases ZZ by 11.
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