Question

Difficulty: MediumMendel's First Law and Monohybrid Inheritance

In humans, normal skin pigmentation is governed by a dominant allele (AA), while albinism is caused by a recessive allele (aa). Match each parental cross combination on the left with its corresponding expected offspring phenotypic and genotypic outcome on the right according to Mendel's First Law.

  • Heterozygous normal individual (AaAa) ×\times Heterozygous normal individual (AaAa)3:13:1 ratio of normal pigmentation to albino offspring (1AA:2Aa:1aa1 AA : 2 Aa : 1 aa)
  • Homozygous normal individual (AAAA) ×\times Albino individual (aaaa)100%100\% normal pigmentation, with all offspring being heterozygous carriers (AaAa)
  • Heterozygous normal individual (AaAa) ×\times Albino individual (aaaa)1:11:1 ratio of normal pigmentation to albino offspring (1Aa:1aa1 Aa : 1 aa)
  • Homozygous normal individual (AAAA) ×\times Heterozygous normal individual (AaAa)100%100\% normal pigmentation, with a 1:11:1 genotypic ratio of non-carriers (AAAA) to carriers (AaAa)

Answer

The parental crosses match their expected offspring outcomes as follows: Aa×AaAa \times Aa produces a 3:13:1 phenotypic ratio of normal to albino offspring; AA×aaAA \times aa produces 100%100\% normal heterozygous carriers (AaAa); Aa×aaAa \times aa produces a 1:11:1 ratio of normal to albino offspring; and AA×AaAA \times Aa produces 100%100\% normal offspring with a 1:11:1 ratio of non-carriers (AAAA) to carriers (AaAa).
Each parental cross follows Mendel's Law of Segregation. A cross between two heterozygotes (Aa×AaAa \times Aa) yields a 3:1 phenotypic ratio (3 normal : 1 albino). A cross between homozygous dominant and homozygous recessive (AA×aaAA \times aa) produces 100% normal carriers (AaAa). A back/test cross (Aa×aaAa \times aa) yields a 1:1 ratio of normal to albino. A cross between homozygous dominant and heterozygous (AA×AaAA \times Aa) produces 100% normal offspring, split equally between non-carriers (AAAA) and carriers (AaAa).

Step-by-Step Solution

1
Analyze the cross Aa×AaAa \times Aa using Mendel's Law of Segregation.
Offspring genotypes are 1AA:2Aa:1aa1 AA : 2 Aa : 1 aa, giving a 3:13:1 ratio of normal skin pigmentation to albinism.
Both parents contribute alleles AA and aa in equal proportions (50% each).
2
Analyze the cross AA×aaAA \times aa.
All offspring receive AA from the first parent and aa from the second parent, yielding 100%Aa100\% Aa.
The dominant allele AA masks the recessive allele aa, making all offspring phenotypically normal carriers.
3
Analyze the cross Aa×aaAa \times aa.
Offspring genotypes are 1Aa:1aa1 Aa : 1 aa, resulting in a 1:11:1 phenotypic ratio of normal to albino offspring.
This is a monohybrid test cross where the phenotypic ratio directly reflects gamete segregation in the heterozygous parent.
4
Analyze the cross AA×AaAA \times Aa.
Offspring genotypes are 1AA:1Aa1 AA : 1 Aa, resulting in 100%100\% normal phenotypes.
The homozygous dominant parent guarantees that every offspring receives at least one AA allele.

Key Concept

Mendel's First Law and Monohybrid Cross Inheritance Ratios
Estimated Time:1m 30s
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