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Difficulty: MediumRate of Reaction and Collision Theory

In an experiment to measure the rate of a chemical reaction, 0.50 g0.50\text{ g} of calcium carbonate reacts completely with excess dilute hydrochloric acid in 25 seconds25\text{ seconds}. What is the average rate of reaction with respect to the loss of mass of calcium carbonate in g s−1\text{g s}^{-1}?

Answer: 0.02 g s^{-1}

Answer

The average rate of reaction with respect to the mass of calcium carbonate consumed is 0.02 g s−10.02\text{ g s}^{-1}.
The average rate of a reaction is calculated as the ratio of the change in amount of reactant or product to the time taken. Substituting the given values gives Rate=0.50 g25 s=0.02 g s−1\text{Rate} = \frac{0.50\text{ g}}{25\text{ s}} = 0.02\text{ g s}^{-1}.

Step-by-Step Solution

1
Extract the given values from the problem statement.
Mass of CaCO3=0.50 g\text{CaCO}_3 = 0.50\text{ g}, Time =25 s= 25\text{ s}.
These parameters define the total change in quantity and the time interval for the reaction.
2
Calculate the average rate of reaction by dividing the change in mass by the time elapsed.
Rate=0.50 g25 s=0.02 g s−1\text{Rate} = \frac{0.50\text{ g}}{25\text{ s}} = 0.02\text{ g s}^{-1}.
The rate of a chemical reaction measures how rapidly a reactant is consumed per unit time.

Key Concept

Rate of Reaction Calculation
Estimated Time:1m 0s
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Topics

Rate of Reaction and Collision Theory