Question

Difficulty: EasyNewton's Laws of Motion and Linear Momentum

Calculate the magnitude of the linear momentum, in kg m s1\text{kg m s}^{-1}, of a body of mass 6 kg6\text{ kg} moving at a constant velocity of 15 m s115\text{ m s}^{-1}.

Answer: 90 kg m s^-1

Answer

The magnitude of the linear momentum is 90 kg m s190\text{ kg m s}^{-1}.
Linear momentum (pp) is the product of an object's mass (mm) and its velocity (vv). Substituting m=6 kgm = 6\text{ kg} and v=15 m s1v = 15\text{ m s}^{-1} yields p=6×15=90 kg m s1p = 6 \times 15 = 90\text{ kg m s}^{-1}.

Step-by-Step Solution

1
Identify the given physical quantities
Mass m=6 kgm = 6\text{ kg} and velocity v=15 m s1v = 15\text{ m s}^{-1}
These are the parameters provided in the problem statement.
2
Apply the linear momentum formula
p=mv=6 kg×15 m s1=90 kg m s1p = mv = 6\text{ kg} \times 15\text{ m s}^{-1} = 90\text{ kg m s}^{-1}
Linear momentum is defined as the product of an object's mass and its velocity.

Key Concept

Linear Momentum Definition
Estimated Time:30s
Rate this question