Question

Difficulty: HardSurds and Rationalisation

If 28103+7+43=k\sqrt{28 - 10\sqrt{3}} + \sqrt{7 + 4\sqrt{3}} = k, where kk is a rational number, find the value of kk.

Answer: 7

Answer

The value of kk is 77.
Simplifying each nested surd into standard binomial surd form gives 28103=53\sqrt{28 - 10\sqrt{3}} = 5 - \sqrt{3} and 7+43=2+3\sqrt{7 + 4\sqrt{3}} = 2 + \sqrt{3}. Combining these terms cancels out the irrational component 3\sqrt{3}, leaving the integer result 5+2=75 + 2 = 7.

Step-by-Step Solution

1
Simplify the nested surd 28103\sqrt{28 - 10\sqrt{3}} into binomial surd form
28103=53\sqrt{28 - 10\sqrt{3}} = 5 - \sqrt{3}
Assuming a form xy3x - y\sqrt{3} and squaring both sides gives x2+3y22xy3=28103x^2 + 3y^2 - 2xy\sqrt{3} = 28 - 10\sqrt{3}. Matching components leads to xy=5xy = 5 and x2+3y2=28x^2 + 3y^2 = 28, which yields integer values x=5x = 5 and y=1y = 1.
2
Simplify the nested surd 7+43\sqrt{7 + 4\sqrt{3}} into binomial surd form
7+43=2+3\sqrt{7 + 4\sqrt{3}} = 2 + \sqrt{3}
Assuming a form u+v3u + v\sqrt{3} and squaring both sides gives u2+3v2+2uv3=7+43u^2 + 3v^2 + 2uv\sqrt{3} = 7 + 4\sqrt{3}. Matching components leads to uv=2uv = 2 and u2+3v2=7u^2 + 3v^2 = 7, which yields integer values u=2u = 2 and v=1v = 1.
3
Sum the simplified expressions to calculate kk
k=7k = 7
Summing (53)+(2+3)(5 - \sqrt{3}) + (2 + \sqrt{3}) results in the irrational parts 3-\sqrt{3} and 3\sqrt{3} cancelling out, leaving 5+2=75 + 2 = 7.

Key Concept

Square Root of a Binomial Surd Expression
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