Despite hydrogen fluoride () possessing stronger individual hydrogen bonds than water (), liquid water has a significantly higher boiling point () than liquid hydrogen fluoride (). What is the primary structural reason for this higher boiling point in water?
- Each water molecule can form an average of four hydrogen bonds in an extensive three-dimensional network, whereas each hydrogen fluoride molecule forms an average of only two hydrogen bonds.Answer
- BThe intramolecular covalent bond between hydrogen and oxygen in water is significantly stronger than the intramolecular covalent bond in hydrogen fluoride.
- COxygen has a higher electronegativity than fluorine, resulting in a larger permanent dipole moment in water molecules.
- DHydrogen fluoride molecules in the liquid state are predominantly attracted by weak London dispersion forces rather than hydrogen bonds.
Answer
Each water molecule can form an average of four hydrogen bonds in an extensive three-dimensional network, whereas each hydrogen fluoride molecule forms an average of only two hydrogen bonds.
The correct answer correctly identifies that the number of hydrogen bonds per molecule determines the bulk physical property. Water possesses 2 hydrogen atoms and 2 lone pairs on oxygen, creating an optimal ratio that allows 4 hydrogen bonds per molecule in a 3D network. Hydrogen fluoride has 3 lone pairs but only 1 hydrogen atom, creating a hydrogen deficit that limits the system to an average of 2 hydrogen bonds per molecule.
Step-by-Step Solution
Key Concept
Hydrogen bonding capacity and network density
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