Question

Difficulty: MediumBasic Trigonometric Ratios, Special Angles, and Identities

What is the exact simplified value of the trigonometric expression sin60+cos30tan45+tan30\frac{\sin 60^\circ + \cos 30^\circ}{\tan 45^\circ + \tan 30^\circ}?

  1. 3(31)2\frac{3(\sqrt{3} - 1)}{2}Answer
  2. B
    332\frac{3 - \sqrt{3}}{2}
  3. C
    36324\frac{3\sqrt{6} - 3\sqrt{2}}{4}
  4. D
    3+13\frac{\sqrt{3} + 1}{3}

Answer

3(31)2\frac{3(\sqrt{3} - 1)}{2}
Substituting the exact values gives a numerator of 3\sqrt{3} and a denominator of 3+13\frac{\sqrt{3}+1}{\sqrt{3}}. Multiplying by the reciprocal of the denominator gives 33+1\frac{3}{\sqrt{3}+1}. Rationalizing the denominator by multiplying top and bottom by (31)(\sqrt{3}-1) simplifies to 3(31)2\frac{3(\sqrt{3}-1)}{2}.

Step-by-Step Solution

1
Substitute the exact standard values for each trigonometric function
sin60=32\sin 60^\circ = \frac{\sqrt{3}}{2}, cos30=32\cos 30^\circ = \frac{\sqrt{3}}{2}, tan45=1\tan 45^\circ = 1, tan30=13\tan 30^\circ = \frac{1}{\sqrt{3}}
Special angles have precise surd representations that must be used in non-calculator assessments.
2
Simplify the numerator and denominator separately
Numerator: 32+32=3\frac{\sqrt{3}}{2} + \frac{\sqrt{3}}{2} = \sqrt{3}. Denominator: 1+13=3+131 + \frac{1}{\sqrt{3}} = \frac{\sqrt{3} + 1}{\sqrt{3}}.
Combine like terms in the numerator and find a common denominator for the terms in the denominator.
3
Divide the numerator by the denominator
33+13=33+1\frac{\sqrt{3}}{\frac{\sqrt{3}+1}{\sqrt{3}}} = \frac{3}{\sqrt{3}+1}
Dividing by a fraction is equivalent to multiplying by its reciprocal.
4
Rationalize the denominator
3(31)(3+1)(31)=3(31)31=3(31)2\frac{3(\sqrt{3}-1)}{(\sqrt{3}+1)(\sqrt{3}-1)} = \frac{3(\sqrt{3}-1)}{3-1} = \frac{3(\sqrt{3}-1)}{2}
Multiply the numerator and denominator by the conjugate (31)(\sqrt{3}-1) to remove the radical from the denominator.

Key Concept

Evaluation and surd simplification of special angle trigonometric expressions
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