An arithmetic progression has a first term of 5 and a common difference of 4. What is the … — JAMB UTME

An arithmetic progression has a first term of $5$ and a common difference of $4$ . What is the $12^{\text{th}}$ term of this progression?

49

The

n^{\text{th}}

term of an arithmetic progression is determined using the formula

T_n = a + (n - 1)d

. Substituting

a = 5

d = 4

, and

n = 12

yields

T_{12} = 5 + 11 \times 4 = 49

, making

49

the correct value.

Identify the given values from the problem statement

First term

a = 5

, common difference

d = 4

, and position

n = 12

These are the standard variables required for calculating terms in an arithmetic progression.

Apply the

n^{\text{th}}

term formula for an arithmetic progression

T_{12} = 5 + (12 - 1) \times 4

The standard formula for the

n^{\text{th}}

term of an AP is

T_n = a + (n - 1)d

Simplify the expression to find the final value

T_{12} = 5 + 11 \times 4 = 5 + 44 = 49

Perform multiplication before addition according to standard order of operations.

Arithmetic Progression

n^{\text{th}}

Term Formula

Estimated Time:45s

Question