What is the exact simplified value of sin60∘+cos45∘\sin 60^\circ + \cos 45^\circsin60∘+cos45∘?3+22\frac{\sqrt{3} + \sqrt{2}}{2}23+2AnswerB52\frac{\sqrt{5}}{2}25C3+12\frac{\sqrt{3} + 1}{2}23+1D3+24\frac{\sqrt{3} + \sqrt{2}}{4}43+2Answer3+22\frac{\sqrt{3} + \sqrt{2}}{2}23+2Substituting the exact values sin60∘=32\sin 60^\circ = \frac{\sqrt{3}}{2}sin60∘=23 and cos45∘=22\cos 45^\circ = \frac{\sqrt{2}}{2}cos45∘=22 gives 32+22=3+22\frac{\sqrt{3}}{2} + \frac{\sqrt{2}}{2} = \frac{\sqrt{3} + \sqrt{2}}{2}23+22=23+2.Step-by-Step Solution1Identify the exact trigonometric values for the special angles.sin60∘=32\sin 60^\circ = \frac{\sqrt{3}}{2}sin60∘=23 and cos45∘=22\cos 45^\circ = \frac{\sqrt{2}}{2}cos45∘=22Standard special angle values in trigonometry.2Substitute the values into the given expression.32+22\frac{\sqrt{3}}{2} + \frac{\sqrt{2}}{2}23+22Direct substitution of known ratio values.3Combine the fractions over the common denominator of 222.3+22\frac{\sqrt{3} + \sqrt{2}}{2}23+2Adding numerators over a shared common denominator.Key ConceptSpecial Angles and Exact Trigonometric ValuesCommon Mistakes