Question

Difficulty: MediumArithmetic and Geometric Progressions (AP and GP)

The 5th5^{\text{th}} term of an arithmetic progression (AP) is 1818 and its 11th11^{\text{th}} term is 4242. Calculate the value of the 20th20^{\text{th}} term of this progression.

Answer: 78

Answer

78
Using the AP general term formula Tn=a+(n1)dT_n = a + (n-1)d, the equations a+4d=18a + 4d = 18 and a+10d=42a + 10d = 42 yield d=4d = 4 and a=2a = 2. Evaluating T20=2+19(4)T_{20} = 2 + 19(4) yields 7878.

Step-by-Step Solution

1
Set up simultaneous equations using the general term formula Tn=a+(n1)dT_n = a + (n-1)d
a+4d=18a + 4d = 18 and a+10d=42a + 10d = 42
Relate given terms to the first term aa and common difference dd.
2
Solve for the common difference dd
6d=24    d=46d = 24 \implies d = 4
Subtracting the 5th term equation from the 11th term equation eliminates aa.
3
Solve for the first term aa
a+16=18    a=2a + 16 = 18 \implies a = 2
Substitute the value of dd back into the first equation.
4
Calculate the 20th term
T20=2+19(4)=78T_{20} = 2 + 19(4) = 78
Apply the nth term formula for n=20n = 20.

Key Concept

Determining terms of an Arithmetic Progression using simultaneous equations
Estimated Time:1m 30s
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