Question

Difficulty: EasyTrigonometric Graphs and Simple Equations

What is the period of the trigonometric function y=3cos(4x)y = 3\cos(4x)?

  1. 9090^\circAnswer
  2. B
    120120^\circ
  3. C
    180180^\circ
  4. D
    14401440^\circ

Answer

The period of the given trigonometric function is 9090^\circ.
The period of a function of the form y=acos(bx)y = a\cos(bx) is given by T=360bT = \frac{360^\circ}{b}. Substituting b=4b = 4 yields T=3604=90T = \frac{360^\circ}{4} = 90^\circ.

Step-by-Step Solution

1
Identify the standard form parameters
For y=3cos(4x)y = 3\cos(4x), amplitude a=3a = 3 and coefficient of xx is b=4b = 4.
The general form of a cosine function is y=acos(bx+c)+dy = a\cos(bx + c) + d.
2
Apply the period formula for trigonometric functions in degrees
Period T=360b=3604=90T = \frac{360^\circ}{b} = \frac{360^\circ}{4} = 90^\circ.
The full cycle of a standard cosine graph completes in 360360^\circ, so multiplying the input by bb compresses the period by a factor of bb.

Key Concept

Period of a Cosine Function
Estimated Time:45s
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