Question

Difficulty: EasyArithmetic and Geometric Progressions (AP and GP)

The 5th5^{\text{th}} term of an arithmetic progression (AP) is 1717 and its common difference is 33. What is the first term of the progression?

  1. 55Answer
  2. B
    22
  3. C
    2929
  4. D
    1-1

Answer

The first term of the progression is 55.
The nthn^{\text{th}} term formula of an arithmetic progression is Tn=a+(n1)dT_n = a + (n - 1)d. Substituting T5=17T_5 = 17, n=5n = 5, and d=3d = 3 gives 17=a+4(3)=a+1217 = a + 4(3) = a + 12. Isolating aa yields a=1712=5a = 17 - 12 = 5.

Step-by-Step Solution

1
Identify the given values and formula for the nth term of an AP.
The formula is Tn=a+(n1)dT_n = a + (n - 1)d, with T5=17T_5 = 17, n=5n = 5, and d=3d = 3.
This formula connects the nth term, the first term, the number of terms, and the common difference.
2
Substitute the known values into the equation.
17=a+(51)×3    17=a+1217 = a + (5 - 1) \times 3 \implies 17 = a + 12.
Subtracting 1 from the term index 5 gives 4, and multiplying by 3 gives 12.
3
Solve for the first term aa.
a=1712=5a = 17 - 12 = 5.
Subtracting 12 from both sides isolates aa.

Key Concept

n-th term of an Arithmetic Progression
Estimated Time:1m 0s
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