Organic Chemistry

102 questions

Question 101Question

Arrange the following organic compounds in order of INCREASING solubility in water, starting with the least soluble compound:

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Answer

The correct sequence from least soluble to most soluble in water is: Pentane, Pentan-1-ol, Butane-1,4-diol, Ethane-1,2-diol.
Water solubility in organic compounds is determined by the balance between hydrophilic (water-attracting) functional groups and hydrophobic (water-repelling) carbon chains. Pentane is non-polar and cannot form hydrogen bonds, making it the least soluble. Pentan-1-ol has one OH-\text{OH} group but a large 5-carbon hydrophobic chain, giving it low solubility. Butane-1,4-diol contains two OH-\text{OH} groups, significantly enhancing hydrogen bonding with water molecules. Ethane-1,2-diol has two OH-\text{OH} groups and the shortest hydrophobic carbon chain (2 carbons), making it the most soluble in water.

Step-by-Step Solution

1
Analyze the functional groups present in each compound.
Pentane has no polar functional groups. Pentan-1-ol has one OH-\text{OH} group. Butane-1,4-diol has two OH-\text{OH} groups. Ethane-1,2-diol has two OH-\text{OH} groups.
Water is a polar solvent that dissolves compounds capable of forming hydrogen bonds through polar functional groups like OH-\text{OH}.
2
Compare the hydrophobic alkyl chain lengths for compounds with the same functional group capability.
Ethane-1,2-diol has a smaller non-polar carbon chain (2 carbons) compared to Butane-1,4-diol (4 carbons).
A larger non-polar alkyl region increases hydrophobic interaction, reducing solubility in water.
3
Establish the complete order of increasing solubility.
Pentane < Pentan-1-ol < Butane-1,4-diol < Ethane-1,2-diol.
Solubility increases with an increasing ratio of hydrophilic functional groups (OH-\text{OH}) to non-polar alkyl chain length.

Key Concept

Solubility of organic compounds based on functional group polarity and hydrophobic alkyl chain length
Question 102Question

Match each polyfunctional organic compound listed on the left with its principal IUPAC functional group suffix on the right, based on IUPAC nomenclature priority rules.

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Items

HOCH2CH2COOH\text{HOCH}_2\text{CH}_2\text{COOH}
CH3COCH2CHO\text{CH}_3\text{COCH}_2\text{CHO}
CH3CH(OH)COCH3\text{CH}_3\text{CH(OH)COCH}_3
CH2=CHCH2OH\text{CH}_2=\text{CHCH}_2\text{OH}

Matches

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Answer

The correct pairings match HOCH2CH2COOH\text{HOCH}_2\text{CH}_2\text{COOH} with -oic acid, CH3COCH2CHO\text{CH}_3\text{COCH}_2\text{CHO} with -al, CH3CH(OH)COCH3\text{CH}_3\text{CH(OH)COCH}_3 with -one, and CH2=CHCH2OH\text{CH}_2=\text{CHCH}_2\text{OH} with -ol.
In IUPAC nomenclature for polyfunctional organic compounds, the principal functional group determines the ending suffix of the compound name. Carboxylic acid (COOH-\text{COOH}) outranks alcohol (OH-\text{OH}), giving -oic acid; aldehyde (CHO-\text{CHO}) outranks ketone (CO-\text{CO}-), giving -al; ketone (CO-\text{CO}-) outranks alcohol (OH-\text{OH}), giving -one; and alcohol (OH-\text{OH}) outranks alkene (C=C\text{C}=\text{C}), giving -ol.

Step-by-Step Solution

1
Identify all functional groups present in each compound.
Compound 1 contains hydroxyl and carboxyl; Compound 2 contains ketone and aldehyde; Compound 3 contains hydroxyl and ketone; Compound 4 contains alkene and alcohol.
Identifying all present functional groups is necessary before applying priority rules.
2
Apply standard IUPAC functional group seniority order.
Priority order: Carboxylic acid (COOH-\text{COOH}) > Aldehyde (CHO-\text{CHO}) > Ketone (CO-\text{CO}-) > Alcohol (OH-\text{OH}) > Alkene (C=C\text{C}=\text{C}).
The group with higher priority determines the principal suffix of the IUPAC name, while lower priority groups are named as prefixes.
3
Assign the principal suffix to each compound.
Compound 1 matches -oic acid, Compound 2 matches -al, Compound 3 matches -one, and Compound 4 matches -ol.
Matches each compound structure to its appropriate IUPAC ending based on priority.

Key Concept

IUPAC Functional Group Seniority Hierarchy
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